Recursive Insertion Sort

Section 3: Recursive Insertion Sort

Recursive Insertion Sort

Do read the recursion blog before procedding with this sorting technique.

Base case: If list has length 1 or zero, return list Inductive step: - Inductively sort slice l[0:len(l)-1] - Insert l[len(l)] into this sorted slice


Let us assume that T(n) is the time to run insertion sort on length n - Time T(n-1) to sort slice seq[0: n-1] - n-1 steps to insert seq[n-1] to sorted slice

Recurrence - T(n)= n-1 + T(n-1) - T(1)= 1

Expanding, we get T(n)= n-1 + T(n-1) = (n-1) + (n-2) + T(n-2) = …. = (n-1) + (n-2) + ….. + 1 = n(n-1)/2 = O(n2)

Question to ponder: What happens when insertion sort is applied to an already sorted list?

Implementation in python
def InsertionSort(seq):

def isSort(seq,k): #Sort slice seq[0:k]
    if k>1:

def insert(seq,k): #Insert seq[k] into sorted seq[0:k-1]
    while pos > 0 and seq[pos] < seq[pos-1]:
        (seq[pos],seq[pos-1])= (seq[pos-1],seq[pos])
        pos = pos - 1

Published by in recursion and tagged algorithms, data structures, python, recursion and sort using 161 words.

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